superky

Admin search was enabled, and now is disabled and everything works fine! thank you

Sorry, one more question.

I was trying to change the words of the button ‘Load More..’ to ‘Load More’, however it is not changing in the frontend.

All in a sudden, the instagram went missing under share button.

Hi,

I wanted to show the publish date only for example 23/6/22, not “Posted on 23/6/22”.

CSS would remove the whole date

table += (function () {
if (fieldname3 >= ‘3’ && fieldname4 >= ‘3’ && fieldname6 >=’3′ && fieldname5 >= ‘2’ ) return ‘<tr><td>’ + fieldname37 + ‘</td><td>’ + fieldname47 + ‘</td><td>’ + fieldname51 + ‘</td><td>’ +
SUM([fieldname1, fieldname2, fieldname3, fieldname4, (function () {
if (fieldname5 != ‘MTH1’ || fieldname5 != ‘MTH2’ || fieldname5 != ‘ECON’ || fieldname5 != ‘CHEM’ || fieldname5 != ‘PHYS’) return 1 * fieldname9;
else {
if (fieldname6 != ‘MTH1’ || fieldname6 != ‘MTH2’ || fieldname6 != ‘ECON’ || fieldname6 != ‘CHEM’ || fieldname6 != ‘PHYS’) return 1 * fieldname10;
else {
if (fieldname7 != ‘MTH1’ || fieldname7 != ‘MTH2’ || fieldname7 != ‘ECON’ || fieldname7 != ‘CHEM’ || fieldname7 != ‘PHYS’) return 1 * fieldname11;
else {
if (fieldname8 != ‘MTH1’ || fieldname8 != ‘MTH2’ || fieldname8 != ‘ECON’ || fieldname8 != ‘CHEM’ || fieldname8 != ‘PHYS’) return 1 * fieldname12;
}
}
}
})()].sort(function (a, b) { return a – b }).reverse().slice(0, 4),
(function () {
if (fieldname5 == ‘MTH1’ || fieldname5 == ‘MTH2’ || fieldname5 == ‘ECON’ || fieldname5 == ‘CHEM’ || fieldname5 == ‘PHYS’) return 1.5 * fieldname9;
else {
if (fieldname6 == ‘MTH1’ || fieldname6 == ‘MTH2’ || fieldname6 == ‘ECON’ || fieldname6 == ‘CHEM’ || fieldname6 == ‘PHYS’) return 1.5 * fieldname10;
else {
if (fieldname7 == ‘MTH1’ || fieldname7 == ‘MTH2’ || fieldname7 == ‘ECON’ || fieldname7 == ‘CHEM’ || fieldname7 == ‘PHYS’) return 1.5 * fieldname11;
else {
if (fieldname8 == ‘MTH1’ || fieldname8 == ‘MTH2’ || fieldname8 == ‘ECON’ || fieldname8 == ‘CHEM’ || fieldname8 == ‘PHYS’) return 1.5 * fieldname12;
}
}
}
})().sort(function (a, b) { return a – b }).reverse().slice(0, 1)) + ‘</td><td> 51 </td><td> 48.75 </td><td> 31 </td><td> 30 </td></tr>’; else return ”;
})();

Chem, phys,econ are the choice values.
I have this code but this wouldnt work for me

Sorry, still cant get it worked.

Let me explain it again in another way, forget the previous requirements mentioned above:

So there are 4 fields(fieldname1,fieldname2,fieldname3,fieldname4), each fields are a dropdown with a list of subjects,
Maths1, Maths2, Chemistry, Music, Economies, History, Physics, Literature, Biology etc.

Each of the 4 fields(fieldname1,fieldname2,fieldname3,fieldname4), has a field to enter their marks(fieldname5,fieldname6,fieldname7,fieldname8).
(fieldname5 is to fieldname1, fieldname6 is to fieldname2, etc)

Now I need to calculate them with the 5 highest marks, including 1.5*best of Maths1/Maths2/Chemistry/Economies/Physics, while others multiply by 1.

Thanks!

It works now!