coachy

Hi francescagr,
the expression ($post_id = “58”) assigns to the variabile $post_id the string value “58” and the assignment is always sucessful so the logical condition is always “true“.

That means that your code is exactly the same of:

if (TRUE) {
        echo "post 58"; 
    } else {
        echo "Not post 58";
    }

and that’s the reason why it always displays “post 58”.

The following code should work:

<?php
    $post_id = get_the_ID();
    if ($post_id == 58) {
        echo "post 58";
    } else {
        echo "Not post 58";
    }
?>

Let us know.
Byez.