PHP Help Please..

  • rellison

    (@rellison)


    15 years, 9 months ago

    I have a section of PHP code that looks like this

    <?php $header = $suf_header_fg_image_type == 'image' ? "<img src='$suf_header_fg_image' alt='".get_bloginfo('name')."'/>" : get_bloginfo('name');
	if ($suf_sub_header_vertical_alignment == "above") {	?>
   		<div class="description"><?php echo bloginfo('description');?></div>
   		<div class="blogtitle"><a href="<?php echo get_option('home');?>"><?php echo $header;?></a></div>

    I need to add an image into the header that is part of a javascript that is loaded previous to this. I want to do something like this..

    <?php $header = "<img id='Rotating1' border='0' '/>";
 $header = $header . $suf_header_fg_image_type == 'image' ? "<img src='$suf_header_fg_image' alt='".get_bloginfo('name')."'/>" : get_bloginfo('name');

    But I keep getting a syntax error in the newly added line. I have sat here for 3 hours now trying to figure this out. Could someone show me the correct format I am supposed to use to do this??

    Thanks

    Rick

Viewing 2 replies - 1 through 2 (of 2 total)
  • wprelief

    (@wprelief)

    15 years, 9 months ago

    Try this:

    <?php $header = "<img id='Rotating1' border='0' />";
 $header = $header . ($suf_header_fg_image_type == 'image' ? "<img src='$suf_header_fg_image' alt='".get_bloginfo('name')."'/>" : get_bloginfo('name'));
    Mark / t31os

    (@t31os_)

    15 years, 9 months ago

    Or.

    <?php
$header = '<img id="Rotating1" border="0" />';
// Concatenate
$header .=
// Ternary conditional check
( 'image' == $suf_header_fg_image_type )
// Assignment if condition true
? '<img src="' . $suf_header_fg_image . '" alt="' . get_bloginfo('name') . '" />'
// Else assignment
: get_bloginfo('name');

Viewing 2 replies - 1 through 2 (of 2 total)

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