PHP conditional for page-image DIV in page.php

pherank
(@pherank)

12 years, 8 months ago

I could use some PHP help (I’m quite rusty with PHP) –

I have the following static pages/slugs:
history, vineyards, wine, contact

And I would like to place a graphic within <div id=”page-image”></div> depending upon the page being displayed. (And I’m custom styling #page-image in “style.css”.)

So I assume I need to add a conditional statement to WordPress “page.php” so that as long as there is no attachment being used, the <div id=”page-image”></div> tags will have the appropriate graphic placed inside the tags.

The graphic names basically match the page names. For now, the URLs to the images are:

http://localhost:8888/wp-content/uploads/2013/07/history_img.jpg
http://localhost:8888/wp-content/uploads/2013/07/vineyards_img.jpg
http://localhost:8888/wp-content/uploads/2013/07/wine_img.jpg
http://localhost:8888/wp-content/uploads/2013/07/contact_img.jpg

So, how do I set this up properly?

Viewing 1 replies (of 1 total)

Thread Starter

(@pherank)

Something like:

<?php
$img_url = '';
if (is_page('history')) {
  $img_url = 'http://localhost:8888/wp-content/uploads/2013/07/history_img.jpg';
} elseif (is_page('vineyards')) {
  $img_url = 'http://localhost:8888/wp-content/uploads/2013/07/vineyards_img.jpg';
} elseif (is_page('wine')) {
  $img_url = 'http://localhost:8888/wp-content/uploads/2013/07/wine_img.jpg';
} elseif (is_page('contact')) {
  $img_url = 'http://localhost:8888/wp-content/uploads/2013/07/contact_img.jpg';
} ?>

<div id="page-image"><?php if($img_url) { $img_url } ?></div>

Or like this?

<div id="page-image"><?php if (!empty($img_url) { echo $img_url } ?></div>

Viewing 1 replies (of 1 total)

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PHP conditional for page-image DIV in page.php

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