Maybe bug in php function parse_url?

I try to get rss from my forum. Link to forum rss looks like this:
http://my_site/forum/external.php?type=rss2&forumids=62 (by this link there is a forum theme). When I tried to do this, I have an error in case, that I see rss of all forum, not for mentioned theme.

When I look in code, in file class-snoopy.php, I see on line 133, in function ‘function fetch($URI)’, line
$URI_PARTS = parse_url($URI);

When I look at variable $URI_PARTS, I see this:

Array ( [scheme] => http [host] => my_site [path] => /forum/external.php [query] => type=rss2& [fragment] => 038;forumids=62 )

So, I see, that forumids=62 linked to section ‘fragment’, though I think, that forumids=62 must be linked to section ‘query’. There is a bug.
I’ll edit file class-snoopy.php, function fetch($URI), and after lines

if (empty($URI_PARTS["path"]))
         $URI_PARTS["path"] = '';

add lines

if (!empty($URI_PARTS['fragment']))
         $URI_PARTS["query"] .= substr($URI_PARTS['fragment'], 4, strlen($URI_PARTS['fragment']));

By the manual of php function parse_url, I see this:

query - after the question mark ?
fragment - after the hashmark #

And I don’t understand, why ?type=rss2&forumids=62 disjointed on query and fragment. Maybe it’s bug? 🙂

Sorry for my bad english…
PS. Уфф, замахался писАть… 🙂