Support » Plugin: LaTeX2HTML » How to make a new line?

• I know the issue I met is too simple, but I just coundn’t find any template which tell me how to make a new line in single block. I can only paste the different paragraph to different blocks, but it’s not convenient.

Here is my code in single block:


\section{Dispersion curve equation}
Lamb wave is a kind of elastic guide wave, its properties and dispersion curve equation can be found in any solid acoustic book. I'll introduce the equation briefly.
\\
­\newline
\linebreak
\vglue
\vspace*{*}
% These are what I tried to make a new line.

The dispersion curve equation can be wrote as:

\begin{equation}\label{eq 1}
\frac{\tan ({k_t}b/2)}{\tan ({k_l}b/2)} = - {\left[ {\frac{4{k^2}{k_l}{k_s}}{(k_s^2 - {k^2})^2}} \right]^{ \pm 1}}
\end{equation}

$+$ and $-$ correspond to symmetry mode and antisymmetry mode, respectively.

Viewing 2 replies - 1 through 2 (of 2 total)
• Now I add the mark of HTML ‘<p>…</p>’ to make a paragraph, i.e. a new line, but it seems weird.

<p>
\section{Dispersion curve equation}
Lamb wave is a kind of elastic guide wave, its properties and dispersion curve equation can be found in any solid acoustic book. I'll introduce the equation briefly.
</p>
<p>
The dispersion curve equation can be wrote as:
\begin{equation}\label{eq 1}
\frac{\tan ({k_t}b/2)}{\tan ({k_l}b/2)} = - {\left[ {\frac{4{k^2}{k_l}{k_s}}{(k_s^2 - {k^2})^2}} \right]^{ \pm 1}}
\end{equation}
</p>
<p>
$+$ and $-$ correspond to symmetry mode and antisymmetry mode, respectively.
</p>


Sorry for the delay. As LaTeX, just put an empty line will generate new line. The following code work for me (however, the \newline and so on command is not supported on the current version of LaTeX2HTML):


\section{Dispersion curve equation}
Lamb wave is a kind of elastic guide wave, its properties and dispersion curve equation can be found in any solid acoustic book. I'll introduce the equation briefly.

The dispersion curve equation can be wrote as:

\begin{equation}\label{eq 1}
\frac{\tan ({k_t}b/2)}{\tan ({k_l}b/2)} = - {\left[ {\frac{4{k^2}{k_l}{k_s}}{(k_s^2 - {k^2})^2}} \right]^{ \pm 1}}
\end{equation}

$+$ and $-$ correspond to symmetry mode and antisymmetry mode, respectively.

Viewing 2 replies - 1 through 2 (of 2 total)
• The topic ‘How to make a new line?’ is closed to new replies.