Support » Plugin: PHP Code Widget » Conditional code gives parse error

  • Resolved indira14

    (@indira14)


    Parse error: syntax error, unexpected ‘endif’ (T_ENDIF) in /home/toko4a1q/public_html/wp-content/plugins/php-code-widget/execphp.php(27) : eval()’d code on line 7

    I am getting this error when trying to use a conditional code:

    <?php
    if(ICL_LANGUAGE_CODE==’en’); ?>
    Sign up for our newsletter to receive news on new products, events and more.’

    <?php echo do_shortcode(‘[newsletter_form]’); ?>

    <?php endif; ?>

    <?php if(ICL_LANGUAGE_CODE==’ne’); ?>
    Meld u hier aan voor nieuwsbrieven met nieuwe producten, evenementen en meer.

    <?php echo do_shortcode(‘[newsletter_form]’); ?>

    <?php endif; ?>

    What am I doing wrong?

    https://wordpress.org/plugins/php-code-widget/

Viewing 1 replies (of 1 total)
  • Plugin Author Samuel Wood (Otto)

    (@otto42)

    You have an incorrect semi-colon after your if statements. That should be a colon instead.

    This forum is not intended for general PHP advice and help. Please look elsewhere for general PHP errors and solutions.

Viewing 1 replies (of 1 total)
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