• Current settings that I have is this simply.

    Only show elements if…
    Surface equals Pastel Paper

    Applies to:
    Pastel Paper Example
    Sizes

    Only show elements if…
    Surface equals Drawing Paper

    Applies to:
    Drawing Paper Example
    Sizes

    Now the condition can only work for one Surface (Condition test), When I removed one of the two conditions the other worked. My size item is a simple list that displays two variable which is (8×12,14×17). I can’t understand why this doesn’t appear when I have both Element applying to the same condition.

    Dunno if this is a bug or if you can replicate it. Let me know what I can do to resolve this or help resolve it.

Viewing 3 replies - 1 through 3 (of 3 total)
  • It may be a bug. The conditions are processed in order (top to bottom), so if your second condition says to hide something, it will be hidden regardless of any condition. Does this explain what is happening?

    Thread Starter Anthony

    (@madburner)

    yeah, it’s suppose to stay hidden only until something equals the right conditions to show it. So this would be more of the opposite of what you’ve mentioned but it’s a similar affect. When I remove on or the other “applies to” it works but not with two “applies to”. So what now?

    I see what you are trying to do. For the example you gave, what you would do is remove ‘sizes’ from both conditions, and make a third condition, ‘if surface equals X OR Y’ and apply that to sizes.

Viewing 3 replies - 1 through 3 (of 3 total)
  • The topic ‘Conditional "Applies to" does work on a second test’ is closed to new replies.