Bug using Choices Callback: field not visible in view mode

Same issue here man.

I opened a ticket and waiting for their reply.

NOTE: if you leave the Parent Option field blank, the field will be visible in View Mode.

Still buggy, but at least that is an option, if you don’t need to specify a Parent

@nathekame
There is no documentation on this that I can find…. but rather than specify a parent option, you can define those parent choices in your custom function (since you write the function to do anything you want). I am successfully using a callback function with no Parent Option.

So try this:
1) create a custom function,
2) reference the function in the field called “Choices Callback”, and
3) Leave the “Parent Option” field blank

Then UM reads the function, and dynamically creates drop-down choices in an array (such as 1, Roberts; 2, Jones; 3, Smith) and then stores the array somewhere, and stores the index value in the user_meta field we chose

Another useful link:
https://wordpress.org/support/topic/please-explain-choices-callback/

• This reply was modified 5 years, 4 months ago by artmerk.

@rachelflara please find below the code i implemented in my case. i built a form that requires filling of state and Local government area(LGA) which is more like state and province in a place like america. so i create a parent dropdown with a list of all states in my country and then wrote a function in my functions.php file using a plugin called “code snippet”. and after i wrote the code and injected it with code snippet, i went over to the form in the LGA dropdown, i put getLGA in the choices callback field (please note that i wrote the function without the brackets) and under the options section you put a * sign because that portion cant be left empty. and then on the parent option section i selected state option . i hope this helps, goodluck

function getLGA() {

global $wpdb;

//get the value from the ‘parent’ field, sent via the AJAX post.
$choice = $_POST[‘parent_option’];

$lgaList = array();

$results = $wpdb->get_results( $wpdb->prepare( “SELECT DISTINCT lga FROM pu_data WHERE state=%s”, $choice));

foreach ( $results as $lgas ) {

$lgaList[$lgas->lga] = $lgas->lga;

}

return $lgaList;

}

Hi @ftpwp

For example, here is a function that should work:

function get_username() {
  // sort by first name
  $users = get_users(array(
    'meta_key' => 'first_name',
    'orderby' => 'meta_value',
  ));
  foreach ( $users as $user ) {
      $user_names[$user->display_name] = $user->display_name;
  }
  return $user_names;
}

So in this example, Choices Callback field would say “get_username” and leave the Parent Option as No selected.

Hi @nathekame,

I have a similar callback function that get datas from the database depending on the parent_option value and I did as you suggested, putting a * in the “Edit choices” as it can’t be empty.

In my form, my child dropdown is filled with all options from my callback function, matching with my parent dropdown selection, so everything is OK for the form display.
The problem I am facing is that after submitting the form, this value is not saved in my user meta.

After some tests, I arrived to the conclusion that if the selected value does not match with a value set in the “Edit choices” field of the dropdown settings, then it is not saved in user meta.
It is a problem for me as I want my dropdown to be filled with options that can be inserted in my db by other users.

Don’t you face the same problem with your LGA dropdown ?

Thanks,