2.7 uses a new function that outputs the logout url. Just use this code
<?php echo wp_logout_url(); ?>
Thanks for the prompt response, Do I just add that code to the anywhere into the sidebar.php file?
Whereever you would like the link to show up. You actually use the code like this.
<a href="<?php echo wp_logout_url(); ?>">Logout</a>
I have added that code into the php file.
It shows two logout buttons which is okay but when i hit the new one i get an error:
“The requested URL /< was not found on this server.”
Please forgive my ignorance..Im very new to editing plugins etc….
Where are you adding the code?
When i look through the file i see:
<li class=”page_item”>‘.__(‘Dashboard’).’
<li class=”page_item”>‘.__(‘Profile’).’
<li class=”page_item”>‘.__(‘Logout’).’
I add it just after that or in theory you could replace the last one although im probably extremely mistaken
Is that in a plugin file though. Try putting it directly in your sidebar.php file.
I put in in the sidebar.php but same thing happened
Is there anyplace in particular i need to put it?
You need to place the code in “al_template.php” in the “ajax-login” folder.
Look for this in al_template.php:
/******* This part is drawn when user IS logged in. *******/
This is where the code needs to go:
<a href="<?php echo get_settings('siteurl') . '/wp-login.php?action=logout&redirect_to=' . $_SERVER['REQUEST_URI']; ?>"><?php _e('Logout'); ?></a>
So now it should look like this:
<a href="<?php echo wp_logout_url('/wp-login.php?action=logout&redirect_to=' . $_SERVER['REQUEST_URI']); ?>" title="Log out">Log out</a>
Hope this helps. 😉
Hi Friends,
This problem is not big problem 😉
Use this codes :
‘.$usp_language[‘logout’].’
For all more webmasters İnformation CLICK HERE
Up to here this is code : )
<a href="'.wp_logout_url(get_option('siteurl')).'" title="'.$usp_language['logout'].'" >'.$usp_language['logout'].'</a>
