WordPress.org

1. HorrorUK
   Member
   Posted 1 year ago #

   I'm trying to show a different image, with a link, depending on whether a user is logged in or not.

   What I'd like to do would be something like this:

   <?php
   if ( is_user_logged_in() ) {
       <A HREF="/"><IMG SRC="<?php bloginfo('template_directory'); ?>/images/createblog.jpg" border="0"></A>
   
   } else {
   <A HREF="/"><IMG SRC="<?php bloginfo('template_directory'); ?>/images/createblogloggedout.jpg" border="0"></A>
   
   };
   ?>

   However, as it doesn't allow commands within the statement, I can't figure out how to do it.

   How would I show an image within that structure?

   Thanks

2. alchymyth
   The Sweeper
   Posted 1 year ago #

   you need to close the php tags before the html code and then open new php tags for more php code:
   principle:
   <?php PHP-CODE ?> HTML-CODE <?php PHP-CODE ?>
   even in an if statement.

   <?php
   if ( is_user_logged_in() ) { ?>
       <a href="/"><img src="<?php bloginfo('template_directory'); ?>/images/createblog.jpg" border="0"></a>
   
   <?php } else { ?>
   <a href="/"><img src="<?php bloginfo('template_directory'); ?>/images/createblogloggedout.jpg" border="0"></a>
   
   <?php };
   ?>

3. HorrorUK
   Member
   Posted 1 year ago #

   Thanks, works perfectly now :)

Topic Closed

This topic has been closed to new replies.