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1. arcab4
   Member
   Posted 4 years ago #

   Issue: i am trying to display all the posts that belong in a certain category. I've figured out how to do that but it shows the results in one long column. What i'd like to do is determine the # of columns to show the results in (in this case 3 columns) and then the posts would be automatically sorted and listed.

   so visually it would be great like this...

   post a post e post i
   post b post f post j
   post c post g post k
   post d post h post l

   The coding I came up with is:

   <?php query_posts('cat=46&orderby=title&order=asc'); ?>
   <table border="1">
   <tr>
   <td valign="top">
   <?php
   $iTotalPosts = 0;
   while (have_posts()) : the_post();
   $iTotalPosts++;
   endwhile;
   
   $iPostCounter = 1;
   $iNumberofColumns= 3;
   $iPostsPerColumns = ceil($iTotalPosts/$iNumberofColumns);
   
   if( $iPostsPerColumns == 0 ){
       $iPostsPerColumns = $iTotalPosts;
   }
   
   while (have_posts()) : the_post();
   if (($iPostCounter % iPostsPerColumns) == 0){
   echo('</td><td valign="top">');
   }
   ?>
   <span class="listings"><a href=" <?php the_permalink(); ?>" title="Permanent
   link to <?php the_title(); ?>"><?php the_title('','','>'); ?></a></span>
   <?php
   $iPostCounter++;
   endwhile;
   ?>
   
   </td>
   </tr>
   </table>

   it's not quite there yet as i get an error message of

   Warning: Division by zero

   the line that causes the error i believe is:

   $iPostsPerColumns = ceil($iTotalPosts/$iNumberofColumns);

   If it's division by zero error, that means the $iNumbersofColumns must not be passing correctly?

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