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1. jcprovideo
   Member
   Posted 3 years ago #

   My syntax is jacked. I tried to use custom fields in an interesting way but I jacked it all up.

   Basically I want to display specific PHP (<?php insert_cform ('6') ; ?>) based on what was written in the custom field. I am hoping my logic was somewhat correct, but I just messed up the syntax. I am more of a CSS guy so any help would be appreciated.

   <?php $jobtype = get_post_meta($post->ID, 'job-type', true);  ?>
          <?php
          		if $jobtype = 'web' { $jobresumetype = '<?php insert_cform ('4') ; ?>' };
   					elseif $jobtype = 'design'{ $jobresumetype = '<?php insert_cform ('5') ; ?>' };
   					else if $jobtype = 'copy'{ $jobresumetype = '<?php insert_cform ('6') ; ?>' };
   				else $jobresumetype = '' };
   					?>
   
             <?php echo $jobresumetype; ?>

2. Otto
   Tech Ninja
   Posted 3 years ago #

   if $jobtype = 'web'

   Wrong. Try this:
   if ($jobtype == 'web')

   Ditto for the other if statements. Also, "elseif" is two words.

3. jcprovideo
   Member
   Posted 3 years ago #

   Thanks OTTO42

   Humm I still got problems though. this is what I have now. It is always pulling insert_cform ('4')

   <?php
          		if ($jobtype == 'web' ) {
   					$jobresumetype = insert_cform ('4') ;
   				}  elseif ($jobtype == 'design') {
   					$jobresumetype = insert_cform ('5') ;
   				}	elseif ($jobtype == 'copy') {
   					$jobresumetype = insert_cform ('6') ;
   				}	else {
   					$jobresumetype == '' ;
   				}
   					?>
             <?php echo $jobresumetype; ?>

4. jcprovideo
   Member
   Posted 3 years ago #

   Nevermind...I got it working. I had this:
   <?php $jobtype = get_post_meta($post->ID, 'job-type', true); ?>
   in the wrong place. Thanks for your help!

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