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1. Mathieu Scholtes
   Member
   Posted 1 year ago #

   Hi, WordPress Friends

   I have this code below, it shows a output from the category slug, on the website. I want it to give it's output only in the code.

   // In that way I can use the slug as a direction for a php include based on the category.

   How do I fix this? (I assume I need to change echo?)

   <?php
   if (is_category( )) {
   $cat = get_query_var('cat');
   $yourcat = get_category ($cat);
   echo $yourcat->slug;
   }
   ?>

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