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'Like' feature for comments... not a Facebook plugin. Please feedback! (1 post)

  1. lacroixca
    Member
    Posted 3 years ago #

    Hello all,

    I would like feedback on my work, because I know this is not perfect at all. I got it working, so it's already fine, but I'm pretty sure there are better way of doing it.

    So what I've done is a basic Facebook-like feature which allows anyone to simply click on the Like button, the pages refreshes and the Like button then becomes Like (1). Then Like (2)... You know.

    An example, you will ask? VoilĂ 
    http://paycers.mechantdesign.com/archives/fan-club/jaime-les-paycers
    Don't worry, it's in French, but I try to code in English so I can get help from you guys. Thus, you should actually look for J'aime (1) instead.

    Here's how I did.

    • Created a 'comment_like' Integer field in 'wp_comments' table.
    • Added in my theme's 'functions.php', the following form:
      <form action="<?php echo home_url( '/wp-content/themes/twentyten/wp-likes-post.php' ); ?>" method="post" class="like-button" name="like-button">
      
      <input type="hidden" id="liked_comment_ID" name="liked_comment_ID" value="<?php comment_ID(); ?>" />
      
      <input type="submit" class="like-button" id="submit" name="submit" value="Like<?php $comment_ID = get_comment_ID(); $likes = get_comment($comment_ID)->comment_likes; if ($likes==0) echo ''; else echo ' (' . $likes . ')'; ?>" />
      
      </form>
    • Created the form action file 'wp-likes-post.php':
      <?php 
      
      $liked_comment_ID = $_POST['liked_comment_ID'];
      
      $db = mysql_connect('localhost', 'LOGIN', 'PASSWORD');
      mysql_select_db('DATABASE',$db);
      
      $sql = "UPDATE wp_comments SET comment_likes = comment_likes +1 WHERE comment_ID = $liked_comment_ID";
      
      $req = mysql_query($sql) or die('SQL Error!'.$sql.''.mysql_error());
      
      mysql_close();
      
      $ref = $_SERVER['HTTP_REFERER'] . '#comment-' . $liked_comment_ID;
      header( 'refresh: 0; url='.$ref); ?>

    I'm happy that it works, but unsatisfied with my methods.

    Few questions.

    First, how do I use $wpdb to connect to the database and update the field for the specified comment? Please don't tell me to look at the Codex; I assure you, I did. However, having the form action script in the themes folder doesn't not seem to recognize the $wpdb... What I mean here is that when I put the script (test version) in the header, it worked, but the same script in my theme's folder did not.

    So, what exact code should replace the UPDATE mySQL part of my form action script?

    Second, what should I write to get a quick redirect after my script? Here again, I read the wp_redirect() Codex page, but to no avail. The current PHP redirect takes a bit of time to reload... I don't know anything about AJAX, would someone know the answer on how to do the database update right on the click (no refresh)?

    That's pretty much it for now. Let me know what you think of it.

    Thank you for your cooperation.

    CAL

    PS: I'm not good in PHP.

    ---

    Also, one thing I would love this feature to have, is a 'Sorry, you need to be registered to Like this comment'.

    People that are not registered would still be able to see, say, Like (2), but wouldn't be able to click it.

    AND, for those that would be registered and logged in, the script would write in the database, in a comment_like_users_ID table, all the ID numbers of the members who Liked the comment. Very much just like Facebook.

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