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1. slamman
   Member
   Posted 8 months ago #

   My site needs 4 individual posts on the front page. Each post is in its own "column". I want to be able to control which posts are in each column by changing the $postid. I have created a widget to do all of this, my problem is solely in getting the posts I want due to the way the "loop" works. Here is my html for one of the columns to illustrate what I am trying to do. Each column is the same as this, I was just trying to change the $postid in the respective column to the post I wanted displayed there:

   <?php query_posts( 'p=$postid' );
   // the Loop
   while (have_posts()) : the_post();?>
   <div class="subFeature-thumb" >
   <img src="<?php echo get_stylesheet_directory_uri() ?>/scripts/timthumb.php?src=<?php echo PostThumbURL(); ?>&w=220&h=100&zc=1" alt="image" />
   </div>
   <div class="subFeature-link">
   <h3><a href="<?php the_permalink() ?>" title="Continue Reading <?php the_title(); ?>"><?php the_title(); ?></a></h3>
   </div>
   <div class="subFeature-byline">
   by <?php the_author() ?> on <?php the_date() ?>
   </div>
   <div class="subFeature-text">
   <?php arc_excerpt('arc_excerptlength_subFeature', 'arc_excerptmore'); ?>
   </div>
    <?php endwhile; ?>

   Any help is greatly appreciated.

2. dheerajsl
   Blocked
   Posted 8 months ago #

   Try removing the quotes <?php query_posts( 'p=$postid' );

   or if that doesnt work try <?php query_posts( 'p=".$postid."' );

3. slamman
   Member
   Posted 8 months ago #

   Thanks for your suggestion, but it doesn't work. I think I see where you are going and I think it is the right track. Initially I thought there was a problem in the way I was using the loop, but thanks to your suggestion and further testing I believe there is a problem with passing the variable in this part:

   <?php query_posts( 'p=$postid' );

   My code is working and I am getting a post...or more correctly every post.

   Prior to inserting the complete code I tested the rest of the code to make sure the variable was available by running this:

   echo $postid;

   This worked resulting in: 42

   This broke the widget:
   <?php query_posts( p=$postid );

   This resulted in no change to the original:
   <?php query_posts( 'p=".$postid."' );

4. slamman
   Member
   Posted 8 months ago #

   Ok I figured this out. I changed the line in question to:

   query_posts( 'p='. $postid );

   makes perfect sense now that I think about about it.

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