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1. negs
   Member
   Posted 2 years ago #

   I am using get_post() to display an array of post ids.

   I am using it properly. I can get
   

   $title = $post_id->post_title;
   echo $title;

   to display the title of the post.

   However, when I try
   

   $excerpt = $post_id->post_excerpt;
   echo $excerpt;

   nothing is displayed. There is content in the post, and I can display when I use post_content. But I want the excerpt because I want to filter out the images in the post.

   Any advice?

2. MichaelH
   Volunteer
   Posted 2 years ago #

   <?php
   //display all post titles, and if an excerpt exists, show it
   $posts=get_posts('post_type=post&showposts=-1');
   if ($posts) {
     foreach($posts as $post) {
       setup_postdata($post);
       ?>
       <p><?php the_time('m.d.y') ?> <a href="<?php the_permalink() ?>" rel="bookmark" title="Permanent Link to <?php the_title_attribute(); ?>"><?php the_title(); ?></a></p>
       <?php
       if ($post->post_excerpt) {
         echo 'excerpt is:' . $post->post_excerpt;
       }
     }
   }
   ?>

   Note that echo $post->post_excerpt; would also work

3. negs
   Member
   Posted 2 years ago #

   I forgot to say... thanks for the reply! I ended up doing something totally different because of a last minute design change. But this was helpful to see.

4. abmcr
   Member
   Posted 2 years ago #

   I am also using get_post() to display a single page

   <?php
   $pagina = & get_post( $dummy_id = 6 );?>
   <h2><?php echo $pagina->post_title;?></h2>
   <?php echo $pagina->post_content; ?>

   However, if i want to show only the text before my page break.... how i do?

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