wetwetwafu
Member
Posted 1 year ago #
i have a function in my function.php that has a line like this:
echo '<img src="http://edward.com/ot/wp-content/themes/default/images/home.png" alt="Home" class="home" /></a> </li> ';
Then i tried this :
echo '<img src="'.get_option('home').'/wp-content/themes/default/images/home.png" alt="Home" class="home" /></a> </li> ';
is there a better way or shorter way to call the template directory?
How do i use the TEMPLATEPATH in this situation? is it posible?
Thanks in advance.
Here's a list:
<?php
echo "ABSPATH ".ABSPATH."<br />";
echo "WP_CONTENT_DIR ".WP_CONTENT_DIR."<br />";
echo "WP_CONTENT_URL ".WP_CONTENT_URL."<br />";
echo "WPINC ".WPINC."<br />";
echo "WP_PLUGIN_DIR ".WP_PLUGIN_DIR."<br />";
echo "WP_PLUGIN_URL ".WP_PLUGIN_URL."<br />";
echo "PLUGINDIR ".PLUGINDIR."<br />";
echo "WPMU_PLUGIN_DIR ".WPMU_PLUGIN_DIR."<br />";
echo "WPMU_PLUGIN_URL ".WPMU_PLUGIN_URL."<br />";
echo "MUPLUGINDIR ".MUPLUGINDIR."<br />";
echo "Parent theme ".TEMPLATEPATH."<br />";
echo "Child theme ".STYLESHEETPATH."<br />";
echo "Parent template_directory ".get_bloginfo('template_directory')."<br />";
echo "Parent template_url ".get_bloginfo('template_url')."<br />";
echo "Child stylesheet_directory ".get_bloginfo('stylesheet_directory')."<br />";
echo "Child stylesheet_url ".get_bloginfo('stylesheet_url')."<br />";
echo "current_theme option ".get_option('current_theme')."<br />";
echo "template option ".get_option('template')."<br />";
echo "stylesheet option ".get_option('stylesheet')."<br />";
?>
wetwetwafu
Member
Posted 1 year ago #
Thanks!
this code works for me. echo "Parent template_directory ".get_bloginfo('template_directory')."<br />";
My code looks like this:
echo '<img src="'.get_bloginfo('template_directory').'/images/home.png" alt="Home" class="home" /></a> </li> ';}
Thanks a lot sir.