• Resolved Eyal_bin

    (@eyal_bin)


    Hi all,

    I am using the following script to show all my categories with images as background (taken from here):

    <?php
    $category_ids = get_all_category_ids();
    foreach($category_ids as $cat_id) {
      $cat = get_category($cat_id);
      $link = get_category_link( $cat_id ); ?>
      <div class="cat-image">
      <a href="<?php echo $link; ?>" title="link to <?php echo $cat->name; ?>">
      <img src="<?php bloginfo('template_url'); ?>/images/<?php echo $cat->slug; ?>.jpg" />
      </a>
      </div>
      <?php
    }
    ?>

    The problem is that this script shows all categories with no exceptions and there are some specific categories that I want to exclude from this list. how do I exclude specific categories from the list using this script?

    Thanks,
    Eyal.

Viewing 2 replies - 1 through 2 (of 2 total)
  • Thread Starter Eyal_bin

    (@eyal_bin)

    Solved it!

    just need to change $category_ids = get_all_category_ids(); to $category_ids = get_categories(); and add relevant arguments

    Michael

    (@alchymyth)

    [edit: well done 😉 ]

    consider to rewrite the code based on get_categories()

    http://codex.wordpress.org/Function_Reference/get_categories

    example:

    <?php
    $args = array( 'exclude' => '3,7,25' );
    $category_ids = get_categories( $args );
    foreach($category_ids as $cat) {
      $link = get_category_link( $cat->term_id ); ?>
      <div class="cat-image">
      <a href="<?php echo $link; ?>" title="link to <?php echo $cat->name; ?>">
      <img src="<?php bloginfo('template_url'); ?>/images/<?php echo $cat->slug; ?>.jpg" />
      </a>
      </div>
      <?php
    }
    ?>

    (untested)

    alternatively, use the list of to-be-excluded cat ids in your code to skip the output;

    example:

    <?php
    $exclude_ids = array( 3, 7, 25 ); //list of the category ids to be excluded//
    $category_ids = get_all_category_ids();
    foreach($category_ids as $cat_id) {
      if( in_array($cat_id, $exclude_ids) ) continue;
      $cat = get_category($cat_id);
      $link = get_category_link( $cat_id ); ?>
      <div class="cat-image">
      <a href="<?php echo $link; ?>" title="link to <?php echo $cat->name; ?>">
      <img src="<?php bloginfo('template_url'); ?>/images/<?php echo $cat->slug; ?>.jpg" />
      </a>
      </div>
      <?php
    }
    ?>

    (untested)

Viewing 2 replies - 1 through 2 (of 2 total)
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