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1. Ruud Evers
   Member
   Posted 1 year ago #
   

   Hi there,

   I have created a custom post type and a custom taxonomy type with two levels of taxonomies. Let me make it clear with the following example:

   Custom post type: Movie
   Custom taxonomy type: Genres
   Custom taxonomy lists:
   - Comedy
   - Comedy sub genre 1
   - Comedy sub genre 2
   - Action
   - Action sub genre 1
   - Action sub genre 2
   - Sci-Fi
   - Sci-Fi sub genre 1
   - Sci-Fi sub genre 2

   What I want to achieve is the following:
   1) When going to the Genre-archive, it should display the main level taxonomies (Comedy, Action, Sci-Fi);
   2) When going to the Comedy-archive, it should display the sub genres;
   3) When going to the sub genre-archive, it should display all movies in that custom genre.

   I have achieved step 3 by using the following code:
   

   <?php
   	$term = $wp_query->queried_object; get_term( $term->slug, 'genres', '', '' ) ;
   	query_posts( array( 'post_type' => 'movie', 'genres' => $term->slug ) );
   	if ( have_posts() ) : while ( have_posts() ) : the_post();
   ?>
   		<h3><?php the_title(); ?></h3>
   		<?php the_content(); ?>
   <?php endwhile; endif; wp_reset_query(); ?>

   Using the code below, I am able to display a full tree view of all my taxonomies:
   

   <?php
   	//list terms in a given taxonomy using wp_list_categories (also useful as a widget if using a PHP Code plugin)
   
   	$taxonomy     = 'genres';
   	$orderby      = 'name';
   	$show_count   = 0;      // 1 for yes, 0 for no
   	$pad_counts   = 0;      // 1 for yes, 0 for no
   	$hierarchical = 1;      // 1 for yes, 0 for no
   	$hide_empty   = 0;
   	$title        = '';
   	$parent       = '';
   
   	$args = array(
   	  'taxonomy'     => $taxonomy,
   	  'orderby'      => $orderby,
   	  'show_count'   => $show_count,
   	  'pad_counts'   => $pad_counts,
   	  'hierarchical' => $hierarchical,
   	  'child_of'     => $parent,
   	  'hide_empty'   => $hide_empty,
   	  'title_li'     => $title
   	);
   ?>
   	<ul>
   		<?php wp_list_categories( $args ); ?>
   	</ul>

   What I am thus looking for is an archive template file that does the following:
   1) Check if it is a main level taxonomy. Yes => show a list of the sub taxonomies
   2) Check if it is a sub-taxonomy. Yes => show a list of the posts in this sub-taxonomy.

   Anyone know if this is possible?

   Thanks a lot!

2. Ruud Evers
   Member
   Posted 1 year ago #
   

   I am progressing a little here. Using the following code, I am able to list all the sub taxonomies using the parents taxonomy id:
   

   <?php
   	$termID = 12;
   	$taxonomyName = "act_groups";
   	$termchildren = get_term_children( $termID, $taxonomyName );
   
   	echo '<ul>';
   	foreach ($termchildren as $child) {
   		$term = get_term_by( 'id', $child, $taxonomyName );
   		echo '<li><a href="' . get_term_link( $term->name, $taxonomyName ) . '">' . $term->name . '</a></li>';
   	}
   	echo '</ul>';
   	?>

   However, so far I haven't been able yet to find a way to get the termID from the database, thus making the function dynamic.

   Any help would be appreciated.

3. Ruud Evers
   Member
   Posted 1 year ago #
   

   This page put me on the right path: http://www.wpbeginner.com/wp-tutorials/how-to-display-child-taxonomy-on-parent-taxonomys-archive-page

   I managed what I wanted by using the following code:
   

   <?php $term = get_term_by( 'slug', get_query_var( 'term' ), get_query_var( 'taxonomy' ) );
   if ($term->parent == 0) { ?>
   	<?php
   		wp_list_categories('taxonomy=YOUR-TAXONOMY-NAME&depth=1&show_count=0&hide_empty=0&title_li=&child_of=' . $term->term_id);
   	?>
   <?php } else { ?>
   	<?php
   		$term = $wp_query->queried_object; get_term( $term->slug, 'YOUR-TAXONOMY-NAME', '', '' ) ;
   		query_posts( array( 'post_type' => 'YOU-CUSTOM-POST-TYPE', 'YOUR-TAXONOMY-NAME' => $term->slug ) );
   		if ( have_posts() ) : while ( have_posts() ) : the_post();
   	?>
   		<h3><?php the_title(); ?></h3>
   		<?php the_content(); ?>
   	<?php endwhile; endif; wp_reset_query(); ?>
   <?php } ?>

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